Problems & Puzzles: Puzzles

Puzzle 1135 Polynomial with consecutive primes such that... Davide Rotondo sent the following puzzle: The polynomial n^4 + 29n^2 + 101 produces 19 consecutive primes whose digits do not alternate parity, for n=1 to 19 The polynomial of Kazmenko and Trofimov | -66n^3 + 3845n^2 - 60897n + 251831 | It produces 46 consecutive primes which I noticed to be peculiar in that for n ranging from 0 to 21 and from 23 to 45 the prime numbers do not have alternating parity digits Q. ARE THERE OTHER POLYNOMIAL THAT PRODUCE MORE CONSECUTIVE PRIMES WITH NO ALTERNATE PARITY DIGITS?

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