Problems & Puzzles: Puzzles

 Puzzle 895. K consecutive quartets of consecutive primes with different ending digit Vic Bold sent the following nice puzzle: Find K consecutive quartets of consecutive primes with different ending digit. He sent the following examples: For K=1: 11, 13, 17, 19 For K=2: 47, 53, 59, 61 53, 59, 61, 67 For K=5 191, 193, 197, 199 193, 197, 199, 211 197, 199, 211, 223 199, 211, 223, 227 211, 223, 227, 229  It was for me not very hard to find a larger example; K=14 2732087209 2732087227 2732087231 2732087263 2732087227 2732087231 2732087263 2732087279 2732087231 2732087263 2732087279 2732087317 2732087263 2732087279 2732087317 2732087321 2732087279 2732087317 2732087321 2732087333 2732087317 2732087321 2732087333 2732087359 2732087321 2732087333 2732087359 2732087447 2732087333 2732087359 2732087447 2732087461 2732087359 2732087447 2732087461 2732087483 2732087447 2732087461 2732087483 2732087489 2732087461 2732087483 2732087489 2732087537 2732087483 2732087489 2732087537 2732087551 2732087489 2732087537 2732087551 2732087563 2732087537 2732087551 2732087563 2732087569 Q. Send your largest example.

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