Problems & Puzzles:
Problems
Problem 38.
Sebastián
Martín Ruiz Prime formulas
Sebastián
Martín Ruiz, a high school teacher from Chipiona, Cadiz, Spain, has came up [1]
with his own prime formulas p(n) and nxt(p)
 p(n)
calculates the nth prime number. See [2]:
(here
means the largest integer less than or equal to x; in Ubasic this corresponds to the function "int(x)" or "floor(x)")
 nxt(p)
calculate the following prime to another given p. See [3]
Sebastian
does not claim that his formulas satisfy one of the desiderata asked
by Hardy and Wright for these mathematical targets:
"Is
there a simple general formula for the nth prime pn (a formula, that is
to say, by which we can calculate the value of pn for any given n with
less labour than by the use of the sieve of Eratosthenes)?"
because
he recognizes that both functions should work slower than the corresponding
algorithms based in the sieve of Erathostenes.
(This
happens due to the very nature of one concept at the core of both
formulas: the exhaustive calculation of the number of divisors of a number
n; this calculation is needed to evaluate the socalled Smarandache
Prime function, a binary one, that constitutes  at the end  the
essential calculation)
Nevertheless
 with this feature against  Sebastián hopes indeed that at least his formulas are better
than the previously produced by others  like Sierpinski, Willans
& Gandhi. See [4]^{ }  in two specific aspects:
 His
formulas do not suppose any previous knowledge or calculation of any
prime number.
 His
formulas are "faster" than any other formulas alike in order
to make the same calculations.
As
a matter of fact Sebastián claims that both formulas are of a polynomial order  k*(n log n)^3  while the previous ones are factorial or
exponential order.
Questions:
1)
Do you agree with the Sebastian's
two before claims?
In
the Ribenboim's interpretation of the Hardy & Wright desiderata
for the prime formula he says:
"What
is intended... is to find a closed
expression for the nth prime p_{n} in
terms of n, by means of functions that are computable
and , if possible, classical" (p.179,
op. cit.)
2)
Dou you think that the Sebastian's
formulas are in terms of n, closed,
computable and
classical?
3)
From a computational
point of view, are the
Sebastian's
prime formulas an improvement or a back step regarding the
Liu Fenghsui' s prime formula? (See Problem
37 in these pages)
4)
Do you devise any way to optimize the Sebastian's
prime formulas?
_________________
Notes:
[1]:
Sebastián Martín Ruiz original publications can be found here: p(n)
and nxt(p). The formulas
were developed in 1999 but published in the SJN at Spring 2000. At
the time of the publications he was considering to be the only author of
the main inner functions [ d(n) and G(n) ]. Only recently he found that
d(n) was already developed, according to "Introducción al la teoría
de números", Ivan Niven & H. S. Zuckerman. Editorial LimusaWiley,
S.A. México, 1969. pp. 888990.
[2]
& [3]: Here are my Ubasiccodes to calculate these functions, and
below the Sebastian's ones for Mathematica.
p(n) 
nxt(p) 
10 input N:clr time:'pnsmr.ub
20 S1=0:Z=2*(int(N*log(N))+1)
30 for K=1 to Z
40 S2=0
50 for J=2 to K
60 S3=0
70 for L=1 to J
80 S3=S3+J\L(J1)\L
90 next L
100 S2=S2+1+(2S3)\J
110 next J
120 S1=S1+1S2\N
130 next K
140 print "The prime";N;"th is=";S1+1;
150 if S1+1<>prm(N) then print "Error":end
160 print "Verified y Right",time:end

10 input P:clr time:'pqsmr.ub
20 S1=0
30 for M=P+1 to 2*P
40 F=1
50 for I=P+1 to M:S2=0
60 for J=1 to I:S2=S2+I\J(I1)\J:next J
70 S2=2S2:F=F*((S2\I))
80 next I
90 S1=S1+F
100 next M
110 print "nxt(";P;")=";P+1+S1,time:end

DD[i_]:=Sum[Floor[i/k]Floor[(i1)/k],{k,1,i}]
FG[n_]:=Sum[1+Floor[(DD[j]2)/j],{j,2,n}]
VIC[n_]:=1+Sum[1Floor[FG[k]/n], {k,1,2*(Floor[n*N[Log[n],15]]+1)}]
Do[Print[VIC[n]," ",Prime[n]],{n,1,25}]

p=Input["Input a
prime number:"]
DD[i_]:=Sum[Floor[i/j]Floor[(i1)/j],{j,1,i}]
G[i_]:=Floor[(2DD[i])/i]
F[m_]:=Product[G[i],{i,p+1,m}]
S[n_]:=Sum[F[m],{m,n+1,2*n}]
Print["nxt(",p,")=",p+1+S[p]]

[4]
P. Ribenboim, The New Book of Prime Number Records, pp. 179186
Solution:
Jud McCranie has suggested to
eliminate the 'floor' or the 'int' functions in the codes
that I originally wrote in Ubasic, using  instead  the integer
division operator (x\y). I have followed his suggestion and the
savings in time of computation has been of .... 33.3%... nothing bad!
Now the codes shown in the table above
reflect that idea.
***
The Jud's idea also can be applied
to the formulas writing, eliminating the clumsy floor brackets so hard to
write in a basic word processor... And I would like if that idea can be
implemented also in the codes for Mathematica, with the same good
results in time savings that we got in Ubasic
***
I (CR) have devised another
important improvement in the codes based in the fact that the calculation
of the number of divisors of a number n, exhaustive via, needs run only
from 1 to isqrt(n) and then multiply for 2 the result obtained. The
changes needed in my codes are:
Function 
Changes in red 
p(n) 
70 for L=1 to isqrt(J)
100 S2=S2+1+(22*S3)\J

nxt(p) 
60 for J=1 to isqrt(I):S2=S2+I\J(I1)\J:next J
70 S2=22*S2:F=F*((S2\I))

The times spent in calculation drop
dramatically!
BTW
nxt(p): while nxt(p) is the following prime to the number p, p itself
needs not to be prime!
***
The Sebastian's formulas introducing
the ideas given by Jud and me (CR), and homogenizing the
subindexes in both formulas, look the following way:
and
in these formulas all the divisions
are integerdivisions
***
The new programs for Mathematica, sent by Sebastián,
are:
Function 
Program 
p(n) 
DD[i_]:=Sum[Quotient[i,k]Quotient[(i1),k],{k,1,Floor[Sqrt[i]]}]
FG[n_]:=Sum[1+Quotient[(22*DD[j]),j],{j,2,n}]
VIC[n_]:=1+Sum[1Quotient[FG[k],n],{k,1,2*(Floor[n*Log[n]]+1)}]
Do[Print[VIC[n]," ",Prime[n]],{n,1,50}] 
nxt(p) 
p=Input["Input a prime number:"]
DD[i_]:=Sum[Quotient[i,j]Quotient[(i1),j],
{j,1,Floor[Sqrt[i]]}]
G[i_]:=Quotient[(22*DD[i]),i]
F[m_]:=Product[G[i],{i,p+1,m}]
S[n_]:=Sum[F[m],{m,n+1,2*n}]
Print["nxt(",p,")=",p+1+S[p]]

***
Patrick De Geest sent the following ideas to
improve the programs a bit more:
1. Using C like notation. The variables thus need to be read
only
once instead of twice. (in large loops the gain in speed can become
important) Therefore I changed:
S3 = S3 + J\L(J1)\L into S3 += J\L(J1)\L
S2 = S2 + 1 + (22*S3)\J into S2 += 1 +(22*S3)\J
S1 = S1 + 1  S2\N into S1 += 1  S2\N
2. Using shortest possible variable names.
(in
large loops the gain can become noticable) Therefore I changed S1 to S,
S2 to T and S3 to U.
3. Cramming all the fornext lines into one long line saves a little
time when dealing with large loops. Of course that clarity in structure
is lost but maybe that is not so important in small routines as p(n).
Combining all these 'shortcuts' gave me the above mentioned runtime
reduction. My final version of p(n) looks like :
10 input N:clr time:'pnsmr.ub
20 S=0:Z=2*(int(N*log(N))+1)
30 for K=1 to Z:T=0:for J=2 to K:U=0:for L=1 to isqrt(J):U+=J\L(J1)\L:next
L:T+=1+(22*U)\J:next J:S+=1T\N:next K
40 print "The prime";N;"th is =";S+1;
50 if S+1<>prm(N) then print "Error":end
60 print "Verified y Right",time:end
The final version of nxt(p) looks like :
(gain
in speed is less pronounced here. I give them anyway as these
optimizations might come handy when developing other future time
critical algorithms)
10 input P:clr time:'pqsmr.ub
20 S=0:for M=P+1 to 2*P:F=1:for I=P+1 to M:T=0:for J=1 to isqrt(I):T=T+I\J(I1)\J:next
J:T=22*T:F*=(T\I):next I:S+=F:next M
30 print "nxt(";P;")=";P+1+S,time:end
***
Sebastian Ruiz has made a very interesting
discovery to his prime formula p(n). You may calculate p(n) not starting
the summa for k since 1 but since any number m less or equal to p(n)
Before 
After 
p(n)=1 + summa from k=1 to... 
p(n)=m + summa from k=m to... 
But this means that of m is the previous prime to p(n),
then this formula is also a formula to calculate recursively prime by
prime starting in any of these. This also means that this formula used
this way is a competitor formula for the nxt(p) formula of Sebastian.
***
As a matter of fact, according to my (C.R.)
implementation of the Ubasic code of the p(n) formula modified to
calculate the series of primes, p(n) is better (faster) than nxt(p)...!!!.
Jud McCranie was asked to confirm the Rivera's
result and this is what he aswered: "Using
p(n), it takes 0.4 seconds to calculate p(75), but it takes 8.4 seconds to
calculate p(1) ...p(75). Using NxtPrm, it takes 0.8 seconds to calculate
p(75) from p(74), and 16.4seconds to calculate p(1) then p(2) ... p(75).
So for these tests, NxtPrm takes twice as long."
***
Sebastian announces that his nxt(p)
function can be formulated in order to obtain, recursively, only the
primes of an arithmetic progression a+d.n, n=>0, gcd(a, d)=1. If you want
to know the expression of that formula and/or the corresponding code in
Mathematica, please request them to Sebastian.
***
One more communication came from S. M.
Ruiz (31/10/2002):
We can transform the sums of products in the
formula for NXT(p) in a nested product:
a+ab+abc=a(1+b(1+c))
For a nested product NP[n] with n levels, we
have NP[n]=O(n). Since d[i]=O(i^(1/2)) with Rivera's
improvement, we get
NestedNXT[n]=NP[d[i],{i,1,n}]=O(n^(3/2)). And since
pn=O(n log n), we get
NestedNXT[pn]=O((n log n)^(3/2)) which is better than
the explicit formula's #pn=O((n log n)^(5/2)).
(By Jonathan Sondow and Sebastián Martín Ruiz)
Here are the corresponding
codes in Mathematica and Ubasic, sent by himself:
Mathematica 
Ubasic 
DD[i_] :=
Sum[Quotient[i, j]  Quotient[i  1, j], {j, 1, Sqrt[i]}]
G[i_] := Quotient[2  2*DD[i], i]
(* n=Bound for Pi[p] prime counting function *)
(* A=Rosser and Schoenfeld inequalities *)
(* B=Nested Product O(nlogn)^(3/2) *)
p = 114
114
While[p < 115,
{n = Floor[N[1.045 + NIntegrate[1/Log[x], {x, 2, p}], 15]];
A = Floor[(n + 1)*Log[n + 1] + (n + 1)*(Log[Log[n + 1]]  0.9385)];
T = G[A]; m = A  1; B = Timing[While[m > p, (T = (T + 1)*G[m]; m)]];
k = p; p = p + 1 + T;
Print["NXT(", k, ")=", p, " ", PrimeQ[p], " ", B]}]

10 input P:clr
time:'pnsmr.ub
15 N=1.39*P/log(P)
17 A=int((N+1)*log(N+1)+(N+1)*(log(log(N+1))0.9385)
18 S3=0
20 for L=1 to isqrt(A)
30 S3=S3+A\L(A1)\L
40 next
50 T= ((22*S3)\A)
120 Z=A1
130 for M=Z to P+1 Step 1
160 S3=0
170 for L=1 to isqrt(M)
180 S3=S3+M\L(M1)\L
190 next L
200 G=((22*S3)\M)
210 T=(T+1)*G
230 next M
240 print "The next prime is=";P+1+T;
250 print time:end 
We can also reduce the order of the explicit
formula p(n) from O(n log n)^(5/2) to O(n log
n)^(3/2)
compute Pi(k) recursively as: pi(k)=pi(k1)+F(k)
where F(k) is the characteristic function of
prime numbers.
There is more improvements in the article than we have written Jonathan
Sondow and me jointly. You can see the version
PDF here :
http://arxiv.org/PS_cache/math/pdf/0210/0210312.pdf .
(This article has been send to The American Mathematical Monthly).
We thank P. Sebah for discussions on the bounds.
***
SMR reported (May, 2003) the following
interesting old reference:
An explicit Formula for the kth prime number,
Sthephen Regimbal, Mathematics Magazine, Volume 48, Issue 4 (Sep. 1975),
pp. 230232.
***
New improvements to the nextprm function came from
William Bouris. When Sebastian revised the Bouris improvement he made one
more improvement to the Bouris work. Here are the successive codes and their
outputs, as ran by Sebastian (who asks where does come from the limit for
the line 15?)
Original code 
Bouris improvement
to the original code 
Sebastian
improvement to the Bouris improvement 
10
input P:clr time:'pqsmr.ub
20 S1=0
30 for M=P+1 to 2*P
40 F=1
50 for I=P+1 to M:S2=0
60 for J=1 to isqrt(I):S2=S2+I\J(I1)\J:next J
70 S2=22*S2:F=F*((S2\I))
80 next I
90 S1=S1+F
100 next M
110 print "nxt(";P;")=";P+1+S1,time:end

5 cls
10 C=0
12 input N:clr time:'pqsmr.ub
15 D=int(N+sqrt(N)+9)
20 S=0
30 F=1
40 for I=(N+1) to D
50 T=0
60 for J=1 to int(sqrt(I))
65 T=T+int(I/J)int((I1)/J)
67 C=C+1
70 next J
75 T=2(2*T)
80 F=F*(int(T/I))
85 S=S+F
90 if T=F then I=D
100 next I
110 print "The next prime after";N;"is";N+1+S;"found
in";C;"steps",time:end
120 goto 12

5 cls
10 C=0
12 input N:clr time:'pqsmr.ub
15 D=int(N+sqrt(N)+9)
30 F=1
40 for I=(N+1) to D
50 T=0
60 for J=1 to int(sqrt(I))
65 T=T+(I\J)((I1)\J)
67 C=C+1
70 next J
75 T=2(2*T)
80 F=F*((T\I))
90 if T=F then goto 110
100 next I
110 print "The next prime after";N;"is";I;"found
in";C;"steps",time:end
120 goto 10

nxtp(100)=101 time =0
sec
nxtp(500)=503 time=4
sec
nxtp(1000)=1009 time=26
sec

nxtp(100)=101
time=0 sec
nxtp(1000)=1009 time=0 sec
nxtp(10000)=10007 time=0 sec
nxtp(100000)=100003 time=1 sec
nxtp(1000000)=1000003 time=2 sec
nxtp(10000000)=10000019 time=25 sec

nxtp(100)=101 time=0 sec
.
.
.
nxtp(10000)=10007 time=0 sec
nxtp(100000)=100003 time=0 sec
nxtp(1000000)=1000003 time=0 sec
nxtp(10000000)=10000019 time=0 sec
nxtp(100000000)=100000007 time=0 sec
nxtp(1000000000)=1000000007 time=0 sec
nxtp(10000000000)=10000000019 time=4 sec
nxtp(100000000000)=100000000003 time=3 sec
nxtp(1000000000000)=1000000000039 time: 98 sec

***
SMR has
developed (March 2004) another formula for the p(n) function, now based in
a totally distinct
characteristic function for the prime numbers recalling the basic arithmetic
function LCM:
His new p(n) formula is
this one:
which he improved as a
calculating tool using the Rosen and Schoenfeld bound:
obtaining:
This last formula (for the
prime p(200) ) is approximately 8.5 times faster than the previous one, and
65 times faster than the faster p(n) function not using the LCM
characteristic function.
SMR now is investigating
the following question "Which is the order of this
algorithm?"
"***
On December 12, 2014, Jonathan Sondow sent
the following related reference to this problem:
Sebastian Martin Ruiz
and Jonathan Sondow,
Formulas for pi(n) and
the nth prime, International Journal of Mathematics and Computer
Science 9 (2014), no. 2, 95–98.
***
